12c^2-26c+12=0

Solution for 12c^2-26c+12=0 equation:

12c^2-26c+12=0

a = 12; b = -26; c = +12;
Δ = b2-4ac
Δ = -262-4·12·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*12}=\frac{16}{24}
=2/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*12}=\frac{36}{24}
=1+1/2
$